Function that will open the project specified by the XPJ path. The function will then load the current project into the global variable currentProject.

Note: Always use this function or the function openprojectdialog() to open a project. This ensures that the global variable currentProject is set. If this variable is not set, several functions in the library may not work as expected.

var xpjpath = "C:/My project/My project.xpj";
openproject(xpjpath);